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RT Daniel Litt: This is actually incredible/incredibly funny.
RT Daniel LittThis is actually incredible/incredibly funny.Andy Jiang: @littmath @__alpoge__ GPT:Take π: P¹ × Sym²(P¹) → Sym³(P¹), (p, {q,r}) ↦ {p,q,r}. R be its ramification divisor;H ⊂ Sym³(P¹) ≅ P³ be hyperplane tangent but not osculating to the small diagonal; X := (P¹ × Sym²(P¹)) (R ∪ π⁻¹(H)) ≅ A³;Y := Sym³(P¹)